(-1)=-3x^2+2x-5

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Solution for (-1)=-3x^2+2x-5 equation: 



(-1)=-3x^2+2x-5

We move all terms to the left:

(-1)-(-3x^2+2x-5)=0

We add all the numbers together, and all the variables

-(-3x^2+2x-5)-1=0

We get rid of parentheses

3x^2-2x+5-1=0

We add all the numbers together, and all the variables

3x^2-2x+4=0

a = 3; b = -2; c = +4;
Δ = b2-4ac
Δ = -22-4·3·4
Δ = -44
Delta is less than zero, so there is no solution for the equation

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